aggiunge esercizio 23
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def is_year_leap(year):
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if year % 4 == 0:
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return True
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else:
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return False
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test_data = [1901, 2000, 2016, 1987]
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test_result = [False, True, True, False]
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for i in range(len(test_data)):
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yr = test_data[i]
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print(yr, "->", end="")
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resutl = is_year_leap(yr)
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if resutl == test_result[i]:
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print("OK")
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else:
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print("Failed")
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