6c5c302c26
Using lsp_id instead of peer as identifier Signed-off-by: Peter Neuroth <pet.v.ne@gmail.com>
32 lines
871 B
Python
32 lines
871 B
Python
from fixtures import * # noqa: F401,F403
|
|
from pyln.testing.utils import RUST
|
|
|
|
import os
|
|
import unittest
|
|
|
|
RUST_PROFILE = os.environ.get("RUST_PROFILE", "debug")
|
|
|
|
|
|
def test_lsps_service_disabled(node_factory):
|
|
"""By default we disable the LSPS service plugin.
|
|
|
|
It should only be enabled if we explicitly set the config option
|
|
`lsps-service=True`.
|
|
"""
|
|
|
|
l1 = node_factory.get_node(1)
|
|
l1.daemon.is_in_log("`lsps-service` not enabled")
|
|
|
|
|
|
@unittest.skipUnless(RUST, 'RUST is not enabled')
|
|
def test_lsps0_listprotocols(node_factory):
|
|
l1, l2 = node_factory.get_nodes(2, opts=[
|
|
{"dev-lsps-client-enabled": None}, {"dev-lsps-service-enabled": None}
|
|
])
|
|
|
|
# We don't need a channel to query for lsps services
|
|
node_factory.join_nodes([l1, l2], fundchannel=False)
|
|
|
|
res = l1.rpc.lsps_listprotocols(lsp_id=l2.info['id'])
|
|
assert res
|